Question

x∽U(-3,3) , P(|x-2|<2) =

• A. 1/2
• B. 1/3
• C. 2/3
• D. 1/4

Answer 1

Answer:

A. 1/2

$f(x)=\frac{1}{b-a}=\frac{1}{3+3}=\frac{1}{6}$

P(|x-2|<2) =P?(-2<x-2<2)=P(0<x<4)

P(0<x<3)=\int_0^3f(x)dx

$=\int_0^3\frac{1}{6}dx$

$=\frac{1}{6}[x]_0^3$

$=\frac{1}{6}(3-0)=\frac{1}{2}$