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x is a three digit natural number such that the difference between the number and its reverse is 99. Then what is the difference between the digit at the hundred's place and the digit at the unit's place of x?

A3

B0

C1

D2

Answer:

C. 1

Read Explanation:

(100a+10b+c)-(100c+10b+a)=99 100a+10b+c-100c-10b-a=99 99a-99c=99 99(a-c)=99 a-c=99/99=1


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