x−1x=3x-\frac{1}{x}=3x−x1=3 then x3−1x3=x^3-\frac{1}{x^3}=x3−x31= A9B18C27D36Answer: D. 36 Read Explanation: (x−1x)3=33=27(x-\frac{1}{x})^3=3^3=27(x−x1)3=33=27(a−b)3=a3−3a2b+3ab2−b3(a-b)^3=a^3-3a^2b+3ab^2-b^3(a−b)3=a3−3a2b+3ab2−b3x3−3x2x×1x+3x×1x2−1x3=27x^3-3x^2x\times\frac{1}{x}+3x\times\frac{1}{x^2}-\frac{1}{x^3}=27x3−3x2x×x1+3x×x21−x31=27x3−3x+3x−1x3=27x^3-3x+\frac{3}{x}-\frac{1}{x^3}=27x3−3x+x3−x31=27x3−1x3−3[x−1x]=27x^3-\frac{1}{x^3}-3[x-\frac{1}{x}]=27x3−x31−3[x−x1]=27x3−1x3−3×3=27</p><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;">x^3-\frac{1}{x^3}-3 \times 3 = 27</p><p data-pxy="true" style="color: rgb(0,0,0); margin-top: 2px; margin-bottom: 2px;">x3−x31−3×3=27</p><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;">x^3-\frac{1}{x^3}=27+9=36$ Read more in App
