Question

If a = 0.125 then what is value of $\sqrt{4a^2-4a+1}+3a$ ?

• A. 1.500
• B. 1.125
• C. 1.250
• D. 1.225

Answer 1

Answer:

B. 1.125

Solution:

Given:

a = 0.125

Concept used:

(A - B)² = A² - 2AB + B²

Calculation:

Now,

$\sqrt{4a^2-4a+1}$

$⇒\sqrt{(1-4a+4a^2)}$

$⇒\sqrt{(1-2a)^2}$

$⇒(1-2a)$

So,

$\sqrt{4a^2-4a+1}+3a$

⇒ (1 - 2a) + 3a

⇒ 1 + a

⇒ 1.125

∴ The required value of  $\sqrt{4a^2-4a+1}+3a$ is 1.125.