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ഒരു നാണയം 5 തവണ കാരക്കുന്ന്. കൃത്യം 2 പ്രാവശ്യം തലകൾ ലഭിക്കാനുള്ള സംഭവ്യത ?

A5/16

B5/8

C16/5

D2/7

Answer:

A. 5/16

Read Explanation:

n=5n=5

x= കൃത്യം 2 തലകൾ = 2

p=12p=\frac{1}{2}

q=112=12q=1-\frac{1}{2}=\frac{1}{2}

P(X=x)=nCxpxqnxP(X=x) = ^nC_x p^xq^{n-x}

P(X=2)=5C2(12)2×(12)3P(X=2) = ^5C_2(\frac{1}{2})^2\times (\frac{1}{2})^3

=5×41×2×122×123=\frac{5 \times 4}{1 \times 2} \times \frac{1}{2^2}\times \frac{1}{2^3}

=516=\frac{5}{16}


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