App Logo

No.1 PSC Learning App

1M+ Downloads
The two sides holding the right-angle in a right-angled triangle are 3 cm and 4 cm long. The area of its circumcircle will be:

A5πcm^2$$

B7πcm^2$$

C6.75π6.75π cm^2$$

D6.25π6.25π cm^2$$

Answer:

6.25π6.25π cm^2$$

Read Explanation:

image.png

The two sides holding the right angle in a right-angled triangle are 3 cm and 4 cm long,

⇒ Length of hypotenuse = (32 + 42)1/2 = 5 cm

⇒ Radius of circum-circle =52=2.5cm=\frac{5}{2}=2.5 cm

∴ Area =227×(2.5)2=\frac{22}{7}\times{(2.5)^2}= 6.25π cm2


Related Questions:

The curved surface area and circumference of the base of a solid right circular cylinder are 1100cm2 and 100cm , repectively.Find the height of the cylinder?

A cuboid of dimensions 18.5 cm x 12.5 cm x 10 cm needs to be painted all over. Find the area to be painted.
On increasing each side of a square by 50%, the ratio of the area of new square formed and the given square will be
ഒരു സമചതുരത്തിന്റെ വിസ്തീർണ്ണം ഒരു വൃത്തത്തിന്റെ വിസ്തീർണ്ണത്തിന്റെ 16/π ആണ്. സമചതുരത്തിന്റെ വശത്തിന്റെയും, വൃത്തത്തിന്റെ വ്യാസത്തിന്റെയും അനുപാതം എന്താണ്?
If the perimeter of a square is 328 m, then the area of the square (in sq.m) is: