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ഒരു സമചതുരത്തിൽ ചുറ്റളവ് 52 സെ.മീ. ആയാൽ ഒരുവശത്തന്റെ നീളമെത്ര?

A16

B14

C13

D15

Answer:

C. 13

Read Explanation:

സമചതുരത്തിന്റെ ചുറ്റളവ് = 4a = 52 a = 52/4 = 13


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