Which term of this arithmetic series is zero: 150, 140, 130 ...?
A16
B17
C15
D18
Answer:
A. 16
Read Explanation:
The first term, a = 150,
common difference is d = -10,
n-th term is 0.
n-th term tn = a + (n-1)d
So 0 = 150 + (n - 1) x-10
- 150 = (n-1)x-10
n - 1 = 150/10 = 15
n=15+ 1 = 16
