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A23

B10

C12

D70

Answer:

$\frac{x^{0.7}}{48}=\frac{36}{x^{2.3}}$

$x^{0.7}\times{x^{2.3}}=36\times48$

$x^{0.7+2.3}=1728$

$x^3=1728$

$x=_3\sqrt{1728}$

$x=12$

Related Questions:

$(5x^2)^4=?$

If x = 2⁸ and $x^x = 2^y$ , then find the value of 'y'.

$\frac{[(5^3)^3]^3}{5^{3+3+3}}=?$