Question

• A. tan A + tan B = 0
• B. tan A = tan B
• C. $$\frac{2tan A+ tan B}{1-tan A tan B}=1$$
• D. $$\frac{2tan A+ tan B}{1+ tan A tan B}=0$$

Answer 1

Answer:

A. tan A + tan B = 0

$tan (A+B) = \frac{tan A + tan B}{1-tanAtanB}$

so tan (A+B)=0

the numerator becomes zero