Acosec θ + tan θ
Bcosec θ - tan θ
Csec θ + tan θ
Dsecθ - tan θ
Acosec θ + tan θ
Bcosec θ - tan θ
Csec θ + tan θ
Dsecθ - tan θ
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Given that 4tanA = 3 , then the value of is
In the figure <CAB=30°, <CPB=60°. AP 10 centimeters. Area of the rectangle ABCD is.............................. square centimeters.