Challenger App

No.1 PSC Learning App

1M+ Downloads

210002999=2^{1000}-2^{999}=

A292^9

B2112^{11}

C21112^{111}

D29992^{999}

Answer:

29992^{999}

Read Explanation:

2100029992^{1000}-2^{999}

21×29992999;xm+n=xm×xn2^1\times2^{999}-2^{999};x^{m+n}=x^m\times{x^n}

2999(21)=2999×1=29992^{999}(2-1)=2^{999}\times1=2^{999}


Related Questions:

image.png
(4+6) x 5 - 3 x (2+8) =

(16)2×(32)493×(42)3=?\frac{(16)^2 \times (3^2)^4}{9^3 \times (4^2)^3}=?

2³ × 5⁴ ന്റെ വില എത്ര ?

(12)3×(12)4×(12)5=?(\frac{1}{2})^3\times(\frac{1}{2})^4\times(\frac{1}{2})^5= ?