Challenger App

No.1 PSC Learning App

1M+ Downloads
25 men can complete a task in 16 days. Four days after they started working, 5 more men, with equal workmanship, joined them. How many days will be needed by all to complete the remaining task?

A15 days

B18 days

C12 days

D10 days

Answer:

D. 10 days

Read Explanation:

Solution: Given: 25 men do the task in 16 days 5 more men had joined them Formula Used: If M1 men can finish W1 work in D1 days and M2 men can finish W2 work in D2 days then, (M1 × D1)/W1 = (M2 × D2)/W2 Calculation: Total work done by 25 men = 25 × 16 = 400 units Work done in 1st four days = 25 × 4 = 100 units Remaining work = 400 - 100 = 300 units Numbers of men joined = 5 Total number of men = 25 + 5 = 30 Remaining work done by 30 men in x days 300 = 30 × x x = 10 ∴ 10 days will be needed by all to complete the remaining task


Related Questions:

Midhun writes the numbers 1 to 100. How many times does he write the digit'0' ?
A pipe can fill a tank with water in 3 hours. Due to leakage in bottom, it takes 3 ½ hours to fill it. In what time the leak will empty the fully filled tank ?
30 men working 5 hours a day can do a task in 16 days. In how many days will 40 men working 6 hours a day do the same task?
A can do a piece of work in 16 days and the same work can be done by B in 24 days, If they work individually on alternate days (i.e., on the first day A does the work and on the second day A was on leave and B done the second-day work and so on.) and A starts the work, then find the total days required to complete the work.
ഒരു ക്ലോക്കിൽ സമയം 8:20 pm കാണിക്കുന്നു എങ്കിൽ മിനിറ്റു സൂചിയും മണിക്കൂർ സൂചിയും തമ്മിലുള്ള കോണളവ് എത്ര ?