2sec²A+ 4cosec²A - 2tan²A - 4cot²A find solutionA2B6C8D4Answer: B. 6 Read Explanation: sec2A=1+tan2Asec^2A=1+tan^2Asec2A=1+tan2Acosec2A=1+cot2Acosec^2A=1+cot^2Acosec2A=1+cot2A2(1+tan2A)+4(1+cot2A)−2tan2A−4cot2A2(1+tan^2A)+4(1+cot^2A)-2tan^2A-4cot^2A2(1+tan2A)+4(1+cot2A)−2tan2A−4cot2A2+2tan2A+4+4cot2A−2tan2A−4cot2A2+2tan^2A+4+4cot^2A-2tan^2A-4cot^2A2+2tan2A+4+4cot2A−2tan2A−4cot2A(2+4)+(2tan2A−2tan2A)+(4cot2A−4cot2A)(2+4)+(2tan^2A-2tan^2A)+(4cot^2A-4cot^2A)(2+4)+(2tan2A−2tan2A)+(4cot2A−4cot2A)6+0+0+=66+0+0+=66+0+0+=6 Read more in App
