Find the value of x if $3^{x+8}=27^{2x+1}$

Challenger App

No.1 PSC Learning App

★

★

★

★

★

1M+ Downloads

Find the value of x if $3^{x+8}=27^{2x+1}$

A0

B1

C2

D-1

Answer:

B. 1

Read Explanation:

$3^{x+8}=27^{2x+1}$

$3^{x+8} = 3^{{6x}+3}$

x + 8 = 6x + 3

5x = 5

x = 1

Read more in App

Related Questions:

$(2.5)^2-(1.5)^2$ എത്ര ?

$\frac {2^3 \times 4^3 \times (6^5)^2} {(36)^4 \times (16)^3} =$

$\sqrt {{40 }+ \sqrt {{69}+ \sqrt{144}}}$

If 9^{48} is divided by 728 what will be the reminder ?

In a geometric progression, the 5th term is 16 times the first term. Find the 7th term if the first term is 2