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8118 is divisible by:

A5

B7

C8

D6

Answer:

D. 6

Read Explanation:

5 is not possible because the last digit should be 5 or 0 8 is not possible because it should be divisible by 2 and 4 , it is not divisible by 4 " last two digit is not multiple of 4) 7 is not divisible by the number sum of these numbers is multiple of 3 so it is divisible by 6 8118=8+1+1+8=18/3=6


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2 കൊണ്ടു ഹരിച്ചാൽ ശിഷ്ടം 1 ഉം 3 കൊണ്ടു ഹരിച്ചാൽ ശിഷ്ടം 2 ഉം 4 കൊണ്ടു ഹരിച്ചാൽ ശിഷ്ടം 3 ഉം 5 കൊണ്ടു ഹരിച്ചാൽ ശിഷ്ടം 4 ഉം കിട്ടുന്ന ഏറ്റവും ചെറിയ സംഖ്യ ഏത്