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A, B and C can do a work in 20, 30 and 60 days respectively. If total Rs, 3000 is given to them, then find their individual share.

ARs. 1000, Rs. 1000 and Rs. 1000

BRs. 1500, Rs. 1000 and Rs. 500

CRs. 1500, Rs. 500 and Rs. 1000

DRs. 500, Rs. 1000 and Rs. 1500

Answer:

B. Rs. 1500, Rs. 1000 and Rs. 500

Read Explanation:

Solution: Given: A, B and C can complete a work in 20 days, 30 days and 60 days respectively. Total wage paid = Rs. 3000 Concept used: Ratio of efficiency = Ratio of wages Formula used: Total work = Efficiency × Time Calculation: Efficiency of A in one day = 1/20 Efficiency of B in one day = 1/30 Efficiency of C in one day = 1/60 Ratio of their efficiency = (1/20) : (1/30) : (1/60) Multiply the above ratio by 60, we get Ratio of their efficiency = 3 : 2 : 1 According to the concept, we have Ratio of wages = 3 : 2 : 1 Let the wage of A, B and C be 3x, 2x and x respectively So, 3x + 2x + x = Rs. 3000 ⇒ 6x = Rs. 3000 ⇒ x = Rs. 500 So, the wage of A = 3x ⇒ Rs. (3 × 500) ⇒ Rs. 1500 And, the wage of B = 2x ⇒ Rs. (2 × 500) ⇒ Rs. 1000 And, the wage of C = x ⇒ Rs. 500 ∴ The salary of A, B and C is Rs. 1500, Rs. 1000 and Rs. 500.


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A,B,C എന്നീ മൂന്ന് പൈപ്പുകൾക്ക് യഥാക്രമം 10, 15, 30 മണിക്കൂർ കൊണ്ട് ഒരു വാട്ടർ ടാങ്ക് ശൂന്യമാക്കാൻ കഴിയും. മൂന്ന് പൈപ്പുകളും ഒരേസമയം തുറന്നാൽ, ടാങ്ക് ശൂന്യമാക്കാൻ എത്ര സമയം (മണിക്കൂറുകൾ) എടുക്കും?