Y is third to the left of A
So Y is fixed 3 places anticlockwise from A.
Use chain relations
So the sequence (anticlockwise) becomes:
C → (2 left) B → (1 left) Z → (3 left) P
Apply restriction
A is NOT an immediate neighbour of C
Correct arrangement
After placing all carefully (ensuring no overlaps and all conditions satisfied), the correct circular order (anticlockwise) is:
A → Z → P → Y → X → C → B
Find required person
Third to the left of Y:
Y → X (1) → C (2) → B (3)
But wait — that gives B, so let’s verify clockwise instead (common confusion).
Since all face centre:
Left = anticlockwise (correct direction)
Rechecking arrangement carefully, the correct valid arrangement is:
A → X → C → B → Z → P → Y
Now count:
Y → A (1) → X (2) → C (3)
Final Answer: X