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3 വയസ്സിന്റെ വ്യത്യാസത്തിൽ ജനിച്ച 5 കുട്ടികളുടെ വയസ്സുകളുടെ തുക 50 ആണെങ്കിൽ, ഏറ്റവും പ്രായം കുറഞ്ഞ കുട്ടിയുടെ വയസ്സ് എത്രയായിരിക്കും ?

A4

B5

C8

D10

Answer:

A. 4

Read Explanation:

കുട്ടികളുടെ പ്രായം x, (x + 3), (x + 6), (x + 9), (x + 12) എന്നിവ ആയാൽ

x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x + 30 =50

5x = 20

x = 4

ഏറ്റവും ഇളയ കുട്ടിയുടെ പ്രായം = x = 4 വയസ്സ്.


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