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A big metal sphere is melted to make spheres of half of the radius of big sphere. How many such small spheres can be made?

A64

B8

C24

D6

Answer:

B. 8

Read Explanation:

The correct answer is Option B (8).

The Ratio Method

Let’s define the dimensions:

  • Big Sphere Radius (RR): Let's call it RR.

  • Small Sphere Radius (rr): The problem says it's half of RR, so r=R2r = \frac{R}{2}.

To find the number of spheres, you divide the Total Volume by the Volume of one small sphere:

Number of Spheres=Volume of Big SphereVolume of Small Sphere \text{Number of Spheres} = \frac{\text{Volume of Big Sphere}}{\text{Volume of Small Sphere}}

Substitute the volume formula 43π(radius)3\frac{4}{3}\pi (\text{radius})^3:

Number=43π(R)343π(R2)3\text{Number} = \frac{\frac{4}{3}\pi(R)^3}{\frac{4}{3}\pi(\frac{R}{2})^3}

Simplifying the Math

  1. Notice that the constant parts (43π\frac{4}{3}\pi) are in both the top and bottom, so they cancel out immediately.

  2. Now you are left with:
    Number=R3(R2)3\text{Number} = \frac{R^3}{(\frac{R}{2})^3}

  3. Apply the cube to the bottom fraction:

  4. Number=R3R38\text{Number} = \frac{R^3}{\frac{R^3}{8}}

  5. When you divide by a fraction, you flip it and multiply:
    Number=R3×8R3 \text{Number} = R^3 \times \frac{8}{R^3}

  6. The R3R^3 cancels out, leaving you with 8.


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