Challenger App

No.1 PSC Learning App

1M+ Downloads
A cylindrical disc of thickness 1 cm is made by melting two solid cylinders of radii 4 cm and 5 cm, and length 6 cm and 4 cm, respectively. The radius of the new cylinder is:

A7 cm

B21 cm

C14 cm

D28 cm

Answer:

C. 14 cm

Read Explanation:

Volume is conserved after melting.

Volume of first cylinder:

V1=πr2h=π(4)2(6)=96πV_1=\pi r^2 h=\pi(4)^2(6)=96\pi

Volume of second cylinder:

V2=πr2h=π(5)2(4)=100πV_2=\pi r^2 h=\pi(5)^2(4)=100\pi

Total volume:

96π+100π=196π96\pi + 100\pi = 196\pi
Let the radius of the new cylindrical disc be (R) cm.

Thickness = 1 cm

Volume of new cylinder:

πR2(1)=196π\pi R^2(1)=196\pi

R2=196R^2 = 196
R=14R = 14

Radius of the new cylinder = 14 cm


Related Questions:

If the length, breath and height of room are 25 m, 15 m and 30 m, respectively, then what will be the area (in m³) of the four walls of the room?
In ∆LMN, medians MX and NY are perpendicular to each other and intersect at Z. If MX = 20 cm and NY = 30 cm, what is the area of ∆LMN (in cm² )?
image.png
പെയിന്റ് ചെയ്ത ഒരു സമചതുരക്കട്ട 27 തുല്യ കഷണങ്ങളാക്കി മാറ്റുന്നു. രണ്ട് മുഖത്ത് മാത്രം പെയിന്റ് ഉള്ള എത്ര ചെറിയ സമചതുരക്കട്ടകൾ ഉണ്ടാകും ?
A cylindrical rod has an outer curved surface area of 8800 cm² . If the length of the rod is 87 cm, then the outer radius (in cm) of the rod, correct to two places of decimal, is: (π=22/7)