Question

A cylindrical object with a density of 0.8 g/cm³ is partially submerged in water. If the volume of object is 0.5 m³, what is the magnitude of the buoyant force acting on it?

• A. 4000 N
• B. 4500 N
• C. 4900 N
• D. 5000 N

Answer 1

Answer:

C. 4900 N

To find the buoyant force, we first need to calculate the weight of the water displaced by the object. Since the object is partially submerged, we'll assume it displaces a volume of water equal to its own volume.

Given:

Density of object = 0.8 g/cm³ (not needed for calculation)
Volume of object (V) = 0.5 m³
Density of water (ρ) = 1000 kg/m³ (approximate)

Weight of water displaced (W) = ρ x V x g

where g is the acceleration due to gravity (approximately 9.8 m/s²)

W = 1000 kg/m³ x 0.5 m³ x 9.8 m/s²
= 4900 N

The magnitude of the buoyant force (Fb) is equal to the weight of the water displaced:

Fb = W
= 4900 N

So, the magnitude of the buoyant force acting on the object is approximately 4900 N.