A natural number, when divided by 4, 5, 6, or 7, leaves a remainder of 3 in each case. What is the smallest of all such numbers?A843B213C423D63Answer: C. 423 Read Explanation: Given:Numbers = 4, 5, 6 or 7Remainder when the number is divided with above numbers = 3Concept used:Find the LCM of the given numbers. LCM - smallest number which will be completely divisibly by the given numbersFor finding the number which will leave the remainder 3, will be (LCM + 3)Calculation:LCM of 4, 5, 6 and 7 = 7×5×3×2×27\times{5}\times{3}\times{2}\times{2}7×5×3×2×2 = 420The number which will leave remainder 3 = 420 + 3⇒ 423Therefore the correct answer is 423. Read more in App