divisibility rule of 8 - the last three digits of the number must be divisible by 8
given number 68XY76, the value of Y will be either 1 or 9
But in that case, a minimum value is required.
we have to take 1
By the divisibility rule of 11, the sums of digits at odd and even places are equal or differ by a number divisible by 11, then the number is also divisible by 11
So, 6 + X + 7 = 8 + 1 + 6
X = 15 - 13
X = 2
Minimum value of 2X + 3Y = 2 × 2 + 3 × 1
2X + 3Y = 4 + 3
2X + 3Y = 7