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A person invested &18,000 in two schemes - Scheme X at 15% p.a. and Scheme Y at 10% p.a., both under simple interest. After 1 year, the total interest from both schemes was ₹2,160. How much was invested in Scheme X?

A₹6000

B₹7000

C₹7200

D₹6200

Answer:

C. ₹7200

Read Explanation:

Let the amount invested in Scheme X be (x).
Then Scheme Y gets (18000 - x).

Both are for 1 year under simple interest.

Step 1: Write interest expressions

Scheme X:
15% of x=0.15x15\% \text{ of } x = 0.15x

Scheme Y:
10% of (18000−x)=0.10(18000−x)10\% \text{ of } (18000 - x) = 0.10(18000 - x)

Total interest given

0.15x+0.10(18000−x)=21600.15x + 0.10(18000 - x) = 2160

Solve

0.15x+1800−0.10x=21600.15x + 1800 - 0.10x = 2160
0.05x+1800=21600.05x + 1800 = 2160
0.05x=3600.05x = 360
x=3600.05=7200x = \frac{360}{0.05} = 7200



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