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a seamless pipe of 600 mm diameter contains a fluid pressure of 3 N/mm². If permissible tensile stress is 120 N/mm², what will be the minimum thickness of the pipe?

A7 mm

B6.5 mm

C8 mm

D7.5 mm

Answer:

D. 7.5 mm

Read Explanation:

Given: p=3N/mm2p = 3N / m m ^ 2 d=600mm=0.6md = 600mm = 0.6m fa=120N/mm2f_{a} = 120 N / m m ^ 2 t >=\frac {p d}{ 2 f_ a} \Rightarrow t>= \frac{3\times600}{ 2\times120} \Rightarrow t=7.5 mm


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