Question

A thin seamless pipe of diameter 'd' m is carrying fluid under a pressure of 'p' kN/cm². If the maximum stress is not exceed 'ơ' kN/cm², the necessary thickness 't' of metal in cm will be given as

• A. $t>=\frac{pd}{2\sigma} cm$
• B. $t>=\frac{100pd}{2\sigma} cm$
• C. $t<=\frac{pd}{2\sigma} cm$
• D. None of these

Answer 1

Answer:

A. $t>=\frac{pd}{2\sigma} cm$

The necessary thickness 't' of metal in cm for a thin seamless pipe carrying fluid under pressure$'p' kN / c m ^ 2$ is given by t >= \frac{100pd}{2\sigma} cm. The hoop stress is given by$\sigma_{h} =\frac{ p d}{ 2 t}$ and the longitudinal stress is given by$\sigma_{L} = \frac{p d}{4 t}$ Equating permissible tensile stress with hoop stress, we get \sigma >= \frac{p d}{ 2 t} Substituting the value of $\sigma$ in the equation for 't', we get the required formula.