A shaft of 50 mm diameter and 0.7 m long is subjected to a torque of 1200 Nm. Calculate the shear stress.A33.3 МРаB67.7 МРаC93.2 МРаD48.9 MPaAnswer: D. 48.9 MPa Read Explanation: Given d = 50 mm, L = 0.7m T = 1200 N-m. τmax=16Tπd3=16×1200×1000π×503=48.9MPa\tau_{max} = \frac {16T}{\pi d^ 3}=\frac{16\times 1200 \times 1000}{\pi \times 50 ^ 3} = 48.9MPaτmax=πd316T=π×50316×1200×1000=48.9MPa Read more in App