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A shaft of 50 mm diameter and 0.7 m long is subjected to a torque of 1200 Nm. Calculate the shear stress.

A33.3 МРа

B67.7 МРа

C93.2 МРа

D48.9 MPa

Answer:

D. 48.9 MPa

Read Explanation:

Given d = 50 mm, L = 0.7m T = 1200 N-m. τmax=16Tπd3=16×1200×1000π×503=48.9MPa\tau_{max} = \frac {16T}{\pi d^ 3}=\frac{16\times 1200 \times 1000}{\pi \times 50 ^ 3} = 48.9MPa


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