Question

A tank holds 5 3/4 liters of water. If 2.375 liters are drained twice, how much water remains?

• A. 1
• B. 1 1/4
• C. 1 3/8
• D. 1 1/2

Answer 1

Answer:

A. 1

Given:

• Initial water in the tank = (5\frac{3}{4}) L = (5.75) L

• Water drained each time = (2.375) L

• Drained twice

Step 1: Total water drained

$2.375 \times 2 = 4.75\text{ L}$

Step 2: Water remaining

$5.75 - 4.75 = 1.00\text{ L}$

Answer:

$\boxed{1\text{ litre}}$