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A thick cylinder is subjected to an internal pressure of 60 MPa. Hoop stress on the outer surface is 150 MPa. Hoop stress on the internal surface is

A105 МРа

B180 MPa

C210 МРа

D135 MPa

Answer:

C. 210 МРа

Read Explanation:

Given: (σh)out=150MPa( \sigma_h )_{out} = 150MPa , P=60MPaP = 60MPa Hoop stress on the internal surface is given by: (σh)out=(σh)inP150=(σh)in60(σh)in=210MPa(\sigma_h )_{out} =( \sigma_h )_{in} -P \Rightarrow 150=( \sigma_h )_{in} -60 \Rightarrow( \sigma_h )_{in} = 210MPa.


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