A thick cylinder is subjected to an internal pressure of 60 MPa. Hoop stress on the outer surface is 150 MPa. Hoop stress on the internal surface isA105 МРаB180 MPaC210 МРаD135 MPaAnswer: C. 210 МРа Read Explanation: Given: (σh)out=150MPa( \sigma_h )_{out} = 150MPa(σh)out=150MPa , P=60MPaP = 60MPaP=60MPa Hoop stress on the internal surface is given by: (σh)out=(σh)in−P⇒150=(σh)in−60⇒(σh)in=210MPa(\sigma_h )_{out} =( \sigma_h )_{in} -P \Rightarrow 150=( \sigma_h )_{in} -60 \Rightarrow( \sigma_h )_{in} = 210MPa(σh)out=(σh)in−P⇒150=(σh)in−60⇒(σh)in=210MPa. Read more in App