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For a rivetted thin cylindrical shell of internal diameter (d), thickness of shell wall (t) and internal pressure (P) with efficiency of longitudinal joint (μi); the hoop stress (σc) will be given by:

Aσc=Pd2t\sigma_{c}=\frac{Pd}{2t}

Bσc=Pd4t\sigma_{c}=\frac{Pd}{4t}

Cσc=Pd2tμl\sigma_{c}=\frac{Pd}{2t\mu_{l}}

Dσc=Pd4tμl\sigma_{c}=\frac{Pd}{4t\mu_{l}}

Answer:

σc=Pd2tμl\sigma_{c}=\frac{Pd}{2t\mu_{l}}

Read Explanation:

For a thin-walled cylindrical shell with internal diameter (d) and wall thickness (t), the circumferential stress (σc\sigma_{c}) is given by σc=Pd2t\sigma_{c} =\frac{P d}{ 2 t} The longitudinal stress (σi\sigma_{i}) is half of the circumferential stress. If the shell is made up of joined riveted plates with the efficiency of a longitudinal joint (μl\mu_{l}) then σc=Pd2tμl\sigma_{c} =\frac {Pd}{2t\mu_{l}}. The efficiency of the circumferential joint (μc\mu_{c}) affects the longitudinal stress, which isσl=Pd4tμl\sigma_{l} = \frac{Pd}{4t\mu_{l}}. The ratio of thickness to radius should be less than 0.1 for a thin-walled cylinder.


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