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A thick cylinder with 10 mm internal diameter and 20 mm external diameter, is subjected to an internal fluid pressure of 60 MPa. The hoop stress at the inner surface is

A140 МРа

B60 MPa

C100 МРа

D40 MPa

Answer:

C. 100 МРа

Read Explanation:

Given: Pi=60MPaP_{i} = 60MPa Po=0P_{o} = 0 ri=5mmr_{i} = 5mm ro=10mmr_{o} = 10mm . σc=Pi[ri2+ro2ro2ri2]σc=60[102+5210252]=100MPa\sigma_{c} =P_{i} [\frac{ r_{i} ^ 2 +r_{o} ^ 2}{ r_{o} ^ 2 -r_{i} ^ 2} ] \Rightarrow \sigma_{c} = 60[\frac{10 ^ 2 + 5 ^ 2}{10 ^ 2 - 5 ^ 2}] = 100MPa

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