App Logo

No.1 PSC Learning App

1M+ Downloads
Abhinav, Bikash and Chetan can complete a piece of work in 16 days, 24 days and 32 days respectively. If Bikash leaves 2 days before completion of the work, then find the total days required to complete the work.

A8 days

B9 days

C6 days

D10 days

Answer:

A. 8 days

Read Explanation:

The total unit of work = L.C.M of (16, 24, 32) = 96 The efficiency of Abhinav = 96/16 = 6 The efficiency of Bikash = 96/ 24 = 4 The efficiency of Chetan = 96/ 32 = 3 Let x be the total number of days required to complete the work. 6x + 4(x - 2) + 3x = 96 6x + 4x - 8 + 3x = 96 13x = 96 + 8 13x = 104 x = 8 days


Related Questions:

A can do a work in 20 days and B in 50 days. If they work on it together for 5 days, then what fraction of work is left?
P, Q and R together do a piece of work for 535. P working alone can do it in 5 days. Q alone can do it in 6 days and R alone can do it in 7 days. Then what will be the share of R for its work.
ഒരു ജോലി 6 ദിവസം കൊണ്ട് P എന്നയാൾ ചെയ്തുതീർക്കുന്നു. അതേ ജോലി Q എന്നയാൾ 18 ദിവസം കൊണ്ടു ചെയ്‌തുതീർക്കുന്നുവെങ്കിൽ രണ്ടുപേരും ചേർന്ന് ജോലി ചെയ്താൽ എത്ര ദിവസം കൊണ്ട് തീർക്കാൻ പറ്റും?
A and B together can complete a work in 12 days. A alone can complete it in 20 days. If B does the work only for the first half of the day daily, then in how many days will A and B together complete the work?
Rama and Hari can together finish a piece of work in 15 day. Rama works twice as fast as Hari, then Hari alone can finish work in :