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Abhinav, Bikash and Chetan can complete a piece of work in 16 days, 24 days and 32 days respectively. If Bikash leaves 2 days before completion of the work, then find the total days required to complete the work.

A8 days

B9 days

C6 days

D10 days

Answer:

A. 8 days

Read Explanation:

The total unit of work = L.C.M of (16, 24, 32) = 96 The efficiency of Abhinav = 96/16 = 6 The efficiency of Bikash = 96/ 24 = 4 The efficiency of Chetan = 96/ 32 = 3 Let x be the total number of days required to complete the work. 6x + 4(x - 2) + 3x = 96 6x + 4x - 8 + 3x = 96 13x = 96 + 8 13x = 104 x = 8 days


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