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Acosec θ + cot θ

Bcosec θ - cot θ

Csec θ - cot θ

Dsec θ + cot θ

Answer:

B. cosec θ - cot θ

Read Explanation:

cosec θ - cot θ

Related Questions:

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figure shows a triangle and its circumcircle what is the radius of the circle

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AC=5 cm, angle ABC =60°

The value of cosec230∘sin⁡245∘+sec⁡260∘tan60∘cosec245∘−sec⁡260∘tan45∘\frac{{\rm cose{c^2}30^\circ {{\rm \sin }^2}45^\circ + {{\rm \sec }^2}60^\circ }}{{\rm tan60^\circ \rm cose{c^2}45^\circ - {{\rm \sec }^2}60^\circ \rm tan45^\circ }}  is:

If cot(2θ + 25°) = tan(θ + 20°), then find cot3θ + sec3θ.
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