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A8 and 6

B2 and 8

C20 and 8

D4 and 20

Answer:

squaring both sides

$2x+9=(13-x)^2$

$2x+9=169-26x+x^2$

$x^2-28x+160=0$

Find two numbers that multiply to 160 and add to 28: $(x-20),(x-8)$

answer is 20&8

Related Questions:

The equation x²-6x+9=0 can be written as:

$p(x) =2x^2+3x+7$ , $q(x)=6x^2+8x-9$ Find $p(x)\times{q(x)}$