A2
B1
C0
D-1
Answer:
2
Related Questions:
The value of cosec230∘sin245∘+sec260∘tan60∘cosec245∘−sec260∘tan45∘\frac{{\rm cose{c^2}30^\circ {{\rm \sin }^2}45^\circ + {{\rm \sec }^2}60^\circ }}{{\rm tan60^\circ \rm cose{c^2}45^\circ - {{\rm \sec }^2}60^\circ \rm tan45^\circ }}tan60∘cosec245∘−sec260∘tan45∘cosec230∘sin245∘+sec260∘ is:
In the figure, AB=4 centimetres, BC =5 centimetres. <B=90° cos C is: