Question

E, F, G, H, K, L and N are sitting around a circular table, facing the centre (but not necessarily in the same order). G sits third to the left of K. N sits second to the left of H. Only K sits between L and N . F is not an immediate neighbour of G. How many people sit between E and N when counted from the right of E ?

• A. 3
• B. 1
• C. 2
• D. 4

Answer 1

Answer:

C. 2

Let’s fix positions step by step (7 people, all facing the centre ⇒ left = clockwise, right = anticlockwise).

1. Place K and G

• Put K anywhere (say position 1).

• G is third to the left of K ⇒ G goes to position 4.

2. Place L and N

• “Only K sits between L and N” ⇒ L and N are on either side of K.
  So they occupy positions 2 and 7.

3. Use N–H condition

• “N sits second to the left of H”
  Try possibilities:

• If N = 2 ⇒ H would be 7 (conflicts with L)

• So N = 7 and L = 2
  Then H must be at position 5.

4. Remaining seats
Now filled:
1(K), 2(L), 4(G), 5(H), 7(N)
Empty: 3 and 6 for E and F.

5. Apply F condition

• F is not a neighbour of G (G at 4 → neighbours 3 and 5)
  So F cannot be at 3 ⇒ F = 6, E = 3.

  Final arrangement (clockwise):

1(K), 2(L), 3(E), 4(G), 5(H), 6(F), 7(N)

Count from right of E (anticlockwise)

From E (position 3), move right (anticlockwise):

• 2 (L)

• 1 (K)

• 7 (N)

People between E and N = L and K = 2 people

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Answer: 2