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Equation of a line passing through (2,3) which is perpendicular to the line 5x+2y-8=0 is :

A2x- 5y=11

B2x+5y=11

C2x-5y=-11

D5x-2y=-11

Answer:

C. 2x-5y=-11

Read Explanation:

slope of a line ax+by+c=0 is -a/b

slope of the line 5x+2y-8=0 is -5/2

If the lines are perpendicular , then

m1×m2=1m_1\times m_2=-1

52×m2=1\frac{-5}{2}\times m_2=-1

m2=1÷52m_2=-1 \div \frac{-5}{2}

m2=1×25m_2=1\times \frac{2}{5}

m2=25m_2=\frac{2}{5}

slope=25point(2,3)slope=\frac{2}{5}point (2,3)

yy1=m(xx1)y-y_1=m(x-x_1)

y3=25(x2)y-3=\frac{2}{5}(x-2)

5(y3)=2(x2)5(y-3)=2(x-2)

5y15=2x45y-15=2x-4

2x5y=112x-5y=-11


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