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If (a+1/a3)2=16(a+1/a-3)^2=16 then find a2+1/a2a^2+1/a^2

A47

B49

C7

D3

Answer:

A. 47

Read Explanation:

(a+1/a3)2=16(a+1/a-3)^2=16

a+1/a3=16=4a+1/a-3=\sqrt{16}=4

a+1/a3=4a+1/a-3=4

a+1/a=4+3=7a+1/a=4+3=7

a2+1/a2=722a^2+1/a^2=7^2-2

=492=47=49-2=47

if a+1/a=ka+1/a=k then a2+1/a2=k22a^2+1/a^2=k^2-2


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