Solution:
Given:
Time taken by F alone = 24 days
Time is taken by G alone = 32 days
G leaves the work 8 days before the completion of work
Formula Used:
Total work = Time taken × Efficiency
Calculation:
Let the total work be LCM of 24 and 32 i.e. 96 unit
Work done by F in 1 day = 96/24 = 4 unit
Work done by G in 1 day = 96/32 = 3 unit
G leaves the work 8 days before the completion of work, so F worked alone for 8 days
Work done by F in 8 days = 4 × 8 = 32 unit
Work left = 96 - 32 = 64 unit
64 unit work is done by both G and F
Time taken to complete 64 unit work = 64/(4 + 3) = 64/7 days
∴ Total time taken = 8 days + 64/7 days = 120/7 days
