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Water is flowing in a pipe of 200 cm diameter under a pressure head of 10000 cm. The thickness of the pipe wall is 0.75 cm. The tensile stress in the pipe wall in MPa is:

A13.0

B100

C133.3

D1305

Answer:

C. 133.3

Read Explanation:

Given: Diameter, d = 200cm = 2m Pressure head, h = 10000cm = 100m Thickness t = 0.75cm = 0.0075m Calculation: σh=pd2t\sigma_{h} =\frac{pd}{2t} Pressure inside the cylinder, P=ρghP = \rho gh σh=(ρgh)d2t=(1000×10×100)22×0.0075=133.3×106=133.3MPa\sigma_{h} = \frac{(\rho gh) d}{2t} = \frac{(1000 \times 10 \times 100) 2}{2 \times 0.0075} = 133.3 \times 10 ^ 6 = 133.3MPa

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