Question

$\frac {2^3 \times 4^3 \times (6^5)^2} {(36)^4 \times (16)^3} =$

• A. 9/2
• B. 9/4
• C. 2/9
• D. ഇവയൊന്നുമല്ല

Answer 1

Answer:

A. 9/2

$4^3 = 2^6$ 

$(6^5)^2 =6^{2\times5}= 6^{10}$

$36^4 =(6^2)^4= 6^8$

$(16)^3 =(2^4)^3= 2^{12}$

$\frac {2^3 \times 2^6 \times 6^{10}} {6^8 \times 2^{12}}$

$=\frac{2^{3+6}\times6^{10}}{6^8\times2^{12}}$

$=\frac{2^9\times6^{10}}{6^8\times2^{12}}$

$=\frac{6^2}{2^3}$

$=\frac{36}{8}$

$=\frac92$