Question

$\frac{0.96^3-0.1^3}{0.96^2+0.096+0.01}=?$

• A. 0.86
• B. 1.06
• C. 0.95
• D. 0.97

Answer 1

Answer:

A. 0.86

$\frac{0.96^3-0.1^3}{0.96^2+0.096+0.01}$

$=\frac{(0.96-0.1)(0.96^2+2\times0.96\times0.1+0.1^2)}{0.96^2+0.096+0.01}$

$=0.96-0.1$

$=0.86$