Challenger App

No.1 PSC Learning App

1M+ Downloads

21001+2999210002998=?\frac{2^{1001}+2^{999}}{2^{1000}-2^{998}}=?

A1

B3

C5

Dഇവയൊന്നുമല്ല

Answer:

D. ഇവയൊന്നുമല്ല

Read Explanation:

The value of the expression is 103\frac{10}{3} (or 3133\frac{1}{3}).

1. Identify the smallest power of 2
To simplify the fraction easily, look for the smallest exponent in the entire expression, which is 998998. We can factor out 29982^{998} from both the numerator and the denominator.

2. Factor the numerator
21001+2999=2998(23+21)2^{1001} + 2^{999} = 2^{998} \cdot (2^3 + 2^1)
=2998(8+2)= 2^{998} \cdot (8 + 2)
=299810= 2^{998} \cdot 10

3. Factor the denominator
210002998=2998(221)2^{1000} - 2^{998} = 2^{998} \cdot (2^2 - 1)
=2998(41)= 2^{998} \cdot (4 - 1)
=29983= 2^{998} \cdot 3

4. Simplify the fraction
Now substitute these back into the original problem:
21001+2999210002998=29981029983\frac{2^{1001}+2^{999}}{2^{1000}-2^{998}} = \frac{2^{998} \cdot 10}{2^{998} \cdot 3}

Cancel out the common 29982^{998} term from both the top and the bottom:
=103= \frac{10}{3}


Related Questions:

(-1)5 +(-1)101 +(-1)200 + (-1)702 = ?

2m2^{m} = 16 ആയാൽ 3(m1)3^{(m -1)} എത്ര ?

(2.5)2(1.5)2(2.5)^2-(1.5)^2  എത്ര ?

if2m=16then find \text{if}\,\,2^m =16\, \text{then find}\,

3m1 3^{m-1}

30+31+32+33+34=x2 3^0 + 3^1 + 3^ 2 + 3^3 + 3^ 4 = x ^ 2 എങ്കിൽ x ൻ്റെ വില എത്ര ?