If x2+1/x2=66 x^2+1/x^2=66x2+1/x2=66 findx−1/xx-1/xx−1/x A10B9C8D6Answer: C. 8 Read Explanation: (x−1/x)2=x2+2−1/x2(x-1/x)^2=x^2+2-1/x^2(x−1/x)2=x2+2−1/x2(x−1/x)2=x2+1/x2−2=66−2=64(x-1/x)^2=x^2+1/x^2-2=66-2=64(x−1/x)2=x2+1/x2−2=66−2=64x−1/x=64=8x-1/x=\sqrt{64}=8x−1/x=64=8 Read more in App
