Question

If $3x^2+ax+12$ is perfectly divisible by(x – 3),then the value of ‘a’ is:

• A. -13
• B. -12
• C. -3
• D. -9

Answer 1

Answer:

A. -13

Given

(x – 3) is divisible the quadratic equation 3x² + ax + 12

⇒ put x = 3

⇒ 27 + 3a + 12 = 0.

⇒ a = -13