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If A=[1  42  3]A = \begin{bmatrix} 1 \ \ 4 \\ 2 \ \ 3 \end{bmatrix}, Find A24A5I? A^2 - 4A - 5I?

A[0  00  0]\begin{bmatrix} 0 \ \ 0 \\ 0 \ \ 0 \end{bmatrix}

B[1  00  1] \begin{bmatrix} 1 \ \ 0 \\ 0 \ \ 1 \end{bmatrix}

C[1  11  1] \begin{bmatrix} 1 \ \ 1 \\ 1 \ \ 1 \end{bmatrix}

D[0  10  1] \begin{bmatrix} 0 \ \ 1 \\ 0 \ \ 1 \end{bmatrix}

Answer:

[0  00  0]\begin{bmatrix} 0 \ \ 0 \\ 0 \ \ 0 \end{bmatrix}

Read Explanation:

[0  00  0]\begin{bmatrix} 0 \ \ 0 \\ 0 \ \ 0 \end{bmatrix}


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The rank of A =A=[0    1     3      1     1      0        1         1   3        1        0        21    1     2         0]A=\begin{bmatrix}0 \ \ \ \ 1 \ \ \ \ \ -3 \ \ \ \ \ \ -1\\ \ \ \ \ \\ \ 1 \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ 1 \\ \\ \ \ \ 3 \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ 2 \\\\ 1 \ \ \ \ 1 \ \ \ \ \ -2 \ \ \ \ \ \ \ \ \ 0 \end{bmatrix} is