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If the radius of a cylinder is increased by 10% and height remains unchanged, then what is the percentage of increase in volume ?

A10%

B20%

C11%

D21%

Answer:

D. 21%

Read Explanation:

v=πr2hv=\pi r^2h

r1=originalradius=1r_1=original radius = 1

r2=increasedradius=1.1×r1r_2=increased radius=1.1 \times r_1

v1=πr12hv_1=\pi r_1^2h

v2=π(1.1×r1)2hv_2=\pi (1.1 \times r_1)^2h

% increase =v2v1v1×100\frac{v_2-v_1}{v_1}\times 100

=(π(1.1×r1)2h)(πr12h)πr12h×100=\frac{(\pi(1.1\times r_1)^2h)-(\pi r_1^2h)}{\pi r_1^2h}\times 100

=πr12h(1.121)πr12h×100=\frac{\pi r_1^2h(1.1^2-1)}{\pi r_1^2h}\times 100

=1.211×100=1.21-1 \times 100

=21=21%


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