Challenger App

No.1 PSC Learning App

1M+ Downloads
If the radius of a cylinder is increased by 10% and height remains unchanged, then what is the percentage of increase in volume ?

A10%

B20%

C11%

D21%

Answer:

D. 21%

Read Explanation:

v=πr2hv=\pi r^2h

r1=originalradius=1r_1=original radius = 1

r2=increasedradius=1.1×r1r_2=increased radius=1.1 \times r_1

v1=πr12hv_1=\pi r_1^2h

v2=π(1.1×r1)2hv_2=\pi (1.1 \times r_1)^2h

% increase =v2v1v1×100\frac{v_2-v_1}{v_1}\times 100

=(π(1.1×r1)2h)(πr12h)πr12h×100=\frac{(\pi(1.1\times r_1)^2h)-(\pi r_1^2h)}{\pi r_1^2h}\times 100

=πr12h(1.121)πr12h×100=\frac{\pi r_1^2h(1.1^2-1)}{\pi r_1^2h}\times 100

=1.211×100=1.21-1 \times 100

=21=21%


Related Questions:

The perimeter of a square is 40 cm. Find the area :

In the figure, APCB is a trapezium. AF is parallel to BC. The diagonals of the trapezium divide it into four parts. The areas of two parts are given as 45 and 15 sq. units. The area of the trapezium in sq units is:

image.png
4 സെ. മീ. ആരമുള്ള കട്ടിയായ ഗോളം ഉരുക്കി 2 സെ. മീ. ആരമുള്ള ചെറു ഗോളങ്ങളാക്കിയാൽ എത്ര ഗോളങ്ങൾ കിട്ടും ?

In the figure of the trapezium a =8 cm, b = 14cm h = 6cm what is its area ?

image.png
The length of two parallel sides of a trapezium are 10 metre and 20 metre. If its height is 8 metre, then what is the area of the trapezium?