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ഒരു ഗോളത്തിന്റെ ഉപരിതലവിസ്തീർണം 64𝛑 cm² ആണെങ്കിൽ അർധഗോളത്തിന്റെ ഉപരിതല വിസ്തീർണം എത്ര?

A48𝛑cm²

B32𝛑cm²

C30𝛑cm²

D36𝛑cm²

Answer:

A. 48𝛑cm²

Read Explanation:

4𝛑r² = 64𝛑 𝛑r² = 64𝛑/4 = 16𝛑 3𝛑r² = 3 × 16𝛑 = 48𝛑 cm²


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