If x+1x=2x + \frac{1}{x}=2x+x1=2, then x5+1x5x^5+\frac{1}{x^5} x5+x51 is A2B3C4D5Answer: A. 2 Read Explanation: x+1x=2x+\frac{1}{x}=2x+x1=2x2+1x=2\frac{x^2+1}{x}=2xx2+1=2x2+1=2xx^2+1=2xx2+1=2xx2−2x+1=0x^2-2x+1=0x2−2x+1=0(x−1)2=0(x-1)^2=0(x−1)2=0x−1=0x-1=0x−1=0x=1x=1x=1x5+1x5x^5+\frac{1}{x^5}x5+x51=15+115=1+1=2=1^5+\frac{1}{1^5}=1+1=2=15+151=1+1=2 Read more in App